Consistent Bayes

$$\pi^{\dagger}_\Lambda(\lambda) := \pi_\Lambda(\lambda)\frac{\pi_{\mathcal{D}}(Q(\lambda))}{\pi^{Q}_{\mathcal{D}}(Q(\lambda))} $$

$\pi^{\dagger}_\Lambda(\lambda) := \pi_\Lambda(\lambda)\frac{\pi_{\mathcal{D}}(Q(\lambda))}{\pi^{Q}_{\mathcal{D}}(Q(\lambda))}$